5x^2-42xy-80y^2=0

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Solution for 5x^2-42xy-80y^2=0 equation:


Simplifying
5x2 + -42xy + -80y2 = 0

Reorder the terms:
-42xy + 5x2 + -80y2 = 0

Solving
-42xy + 5x2 + -80y2 = 0

Solving for variable 'x'.

Factor a trinomial.
(x + -10y)(5x + 8y) = 0

Subproblem 1

Set the factor '(x + -10y)' equal to zero and attempt to solve: Simplifying x + -10y = 0 Solving x + -10y = 0 Move all terms containing x to the left, all other terms to the right. Add '10y' to each side of the equation. x + -10y + 10y = 0 + 10y Combine like terms: -10y + 10y = 0 x + 0 = 0 + 10y x = 0 + 10y Remove the zero: x = 10y Simplifying x = 10y

Subproblem 2

Set the factor '(5x + 8y)' equal to zero and attempt to solve: Simplifying 5x + 8y = 0 Solving 5x + 8y = 0 Move all terms containing x to the left, all other terms to the right. Add '-8y' to each side of the equation. 5x + 8y + -8y = 0 + -8y Combine like terms: 8y + -8y = 0 5x + 0 = 0 + -8y 5x = 0 + -8y Remove the zero: 5x = -8y Divide each side by '5'. x = -1.6y Simplifying x = -1.6y

Solution

x = {10y, -1.6y}

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